Question: Where, for surface flaws: K = 1 . 1 ( a Q ) 1 2 and for embedded flaws: K = ( a Q )

Where, for surface flaws:
K=1.1(aQ)12
and for embedded flaws:
K=(aQ)12
A thick plate of steel contains a central through-thickness flaw of length 16 mm , which is
subjected to a stress of 350 MPa applied perpendicularly to the flaw plane. The 0.2% flow stress
of the material is 1350 MPa.
a) Calculate the plastic zone size and the effective stress intensity (Keff.) at the crack tip,
making reasonable assumptions about the state of stress.
b) If, after heat treatment, the flow stress of the steel dropped to 800 MPa , what would the
plastic zone size be under the applied stress of 350 MPa , and what conclusions would you
draw about the use of LEFM (with the small scale yielding (SSY) assumption)?
(Note: if the plastic zone is less than 2-3% of crack size, iteration is not required for computation)
Where, for surface flaws: K = 1 . 1 ( a Q ) 1 2

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