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MATH $2554$

Your Turn:

Find $f^{\text{'}}(x)$ given that $f(x)=\sqrt[3]{x}-\frac{3}{\sqrt[\phantom{2}]{x}}{e}^5.$

A$.\frac{1}{3}{x}^{-\frac{2}{3}}-\frac{3}{2}{x}^{-\frac{1}{2}}5e^4$

B$.\frac{1}{3}{x}^{-\frac{2}{3}}\frac{3}{2}{x}^{-\frac{3}{2}}5e^4$

C$.\frac{1}{3}{x}^{-\frac{2}{3}}-\frac{3}{2}{x}^{-\frac{1}{2}}$

D$.\frac{1}{3}{x}^{-\frac{2}{3}}\frac{3}{2}{x}^{-\frac{3}{2}}$

E$.$ None of the above

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