Question: why is correct the output of this code? #include int main( void ) { char val[] = one; if (val[1] = 'o') printf(correct); else printf(incorrect);
why is correct the output of this code? #includeint main( void ) { char val[] = "one"; if (val[1] = 'o') printf("correct"); else printf("incorrect"); }
Step by Step Solution
There are 3 Steps involved in it
1 Expert Approved Answer
Step: 1 Unlock
Question Has Been Solved by an Expert!
Get step-by-step solutions from verified subject matter experts
Step: 2 Unlock
Step: 3 Unlock
