Question: why z = log(-1 +- 2^1/2) + 2*pi*n*i not z = log(-1 +- 2^1/2) + 2*pi*n

why z = log(-1 +- 2^1/2) + 2*pi*n*i not z = log(-1 +- 2^1/2) + 2*pi*n

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