Question: Will the deadlock be avoided by the above cases and why? I really need help on this. The code for part A chopstick is import

Will the deadlock be avoided by the above cases and why? I really need help on this.

The code for part A chopstick is Will the deadlock be avoided by the above cases and why? I

really need help on this. The code for part A chopstick is

import java.util.concurrent.Semaphore; public class Chopstick i private int ID private boolean free // hint: use a local variable to indicate whether the chopstick is free (lying on the table), e.g private boolean free; Chopstick (int ID) [ this.IDID this.free-true synchronized void take) throws InterruptedException i if (this.free) this.free-false; else this.wait) take ) synchronized void release ( if (this.free false) this.free-true this.notify public int getIDf return (ID) import java.util.concurrent.Semaphore; public class Chopstick i private int ID private boolean free // hint: use a local variable to indicate whether the chopstick is free (lying on the table), e.g private boolean free; Chopstick (int ID) [ this.IDID this.free-true synchronized void take) throws InterruptedException i if (this.free) this.free-false; else this.wait) take ) synchronized void release ( if (this.free false) this.free-true this.notify public int getIDf return (ID)

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