] Write a Matlab code which is able to implement the "Gauss Jordan Method" for any problem. Test your code for a civil engineering analysis problem below. "Submit a file which includes both your code(it is not allowed to use brief codes in MATLAB, it is expected write an entire script and the results. The truss in figure below is called statically determinant, because three linearly independent equations can be set up to solve for the six forces. There are three member forces and three support reactions to be determined but only three force equations can be written. This truss is called statically indeterminate. Using the equation of equilibrium for each joint 1.2 and 3, respectively determine the all member forces and support reaction forces. Please use the "Gauss Jordan Methods" to solve the linear sets of equations. 1000 lb F 902 30 H Hint: For cach joint, please write an equation of equilibrium by using Newton's 2.Law in terms of static. Fx=-F, cos 30+F,cos 60 = 0 Fr=-1000-F, sin 30-F, sin 60 = 0 EF: =H, +F, cos 30+F, = 0 F, =V+F sin 30 = 0 Fy=-F,-F, cos 60 = 0 F, -V, +F, sin 60 - 0 Activate Windows Go to Settings to activate Windows. ] Write a Matlab code which is able to implement the "Gauss Jordan Method" for any problem. Test your code for a civil engineering analysis problem below. "Submit a file which includes both your code(it is not allowed to use brief codes in MATLAB, it is expected write an entire script and the results. The truss in figure below is called statically determinant, because three linearly independent equations can be set up to solve for the six forces. There are three member forces and three support reactions to be determined but only three force equations can be written. This truss is called statically indeterminate. Using the equation of equilibrium for each joint 1.2 and 3, respectively determine the all member forces and support reaction forces. Please use the "Gauss Jordan Methods" to solve the linear sets of equations. 1000 lb F 902 30 H Hint: For cach joint, please write an equation of equilibrium by using Newton's 2.Law in terms of static. Fx=-F, cos 30+F,cos 60 = 0 Fr=-1000-F, sin 30-F, sin 60 = 0 EF: =H, +F, cos 30+F, = 0 F, =V+F sin 30 = 0 Fy=-F,-F, cos 60 = 0 F, -V, +F, sin 60 - 0 Activate Windows Go to Settings to activate Windows