Write a MIPS program that asks the user to input string. The program then removes all space characters from the string. The program finally displays the resulting string without spaces.

The following C code shows the proposed algorithm. The string is traversed with two indices, called old_index and new_index, where the latter always takes a value less or equal to the former. When a non?space character is found, the character at position old_index is copied to position new_index, and both indices are incremented. When a space is found, the current character is not copied, and only old_index is incremented. The algorithm stops when a null character is found.

#include int main () /7 Read string char s[100] printf ("Enter string: "); gets (s); // Remove spaces char c int old index0 int new index-0; do / Read character cs[old_index] // Old position moves ahead old indext+ /7 If it's a space, ignore if (c '') continue; 7Copy character s [new index] - ci // New position moves ahead new index++ while (c)i // Print result printf("New string: %s ", s)