Write a program that asks the user to enter a menu of numbers: ( for example: 100, 150, 170, 200). Based on number entered, output the binary equivalent. Implement using an if else chain. Repeat the process using a do-while loop

here's the code that i did !

double selection;
11	- cout << "Enter a Hexadecimal number; (15 , 20 , 25 , 30 , 35 )";
12	- >>endl ;
13	- cin >> selection;
14	-
15	-
16	- if (selection == 15)
17	- cout << "Binary # is: 01111" << endl;
18	- else if (selection == 20)
19	- cout << "Binary # is: 010100" << endl;
20	- else if (selection == 25)
21	- cout << "Binary # is: 011001" << endl;
22	- else if (selection == 30)
23	- cout << "Binary # is: 011110" << endl;
24	- else if (selection == 35)
25	- cout << "Binary # is: 010011" << endl;
26	- else
27	- cout << " invalid selection" << endl;