Write a program that reverses the order of the elements in each row of the matrix.

Print out the resulting matrix. import java.io$.*$ ;

public class Ch$67$ex$06\_$ReverseRow$\_4$a$\_$stu

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static int$[][]$ data $=\{\{3,2,5\},//$ ragged array, "data"

$\{1,4,4,8,13\},$

$\{9,1,0,2\},$

$\{0,2,6,3,-1,8\},$

$\{-1,-2,-3,4,5,45\},$

$\{56\},$

$\{0,1,2,3,4,5,6,7\}\}$;

private static void printArray$()$

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PLN$("")$;

for $($ int row$=0$; row $<$ data.length; row$++)//$ process by rows

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for $($ int col$=0$; col $<$ data$[$row$].$length$-1$; col$++)//$ process each column of a row

P$($ data$[$row$][$col$]+",")$; $//$ scope is one line, not a block

PLN$($ data$[$row$][$data$[$row$].$length$-1])$;

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public static void main $($ String$[]$ args $)$

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printArray$()$; $//$ print out the initial array

for $($ int row$=0$; row $<$ data.length; row$++)//$ process all rows

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int endIdx $=$ data$[$row$].$length; $//$ determine ending column number

for $($ int col$=0$; col $<$ endIdx$/2$ ; col$++)//$# use half the row; even$/$odd$!$ #$//$

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$//----$ insert code here $----//$

$//$# standard swap #$//$

$//$# put end col into start col #$//$

$//$# be careful with 'off by one' #$//$

$\}//$# half cols because of swapping #$//$

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printArray$()$; $//$ print out the row$-$reversed array

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public static void P$($Object x$)\{$System$.$out.print$($x$)$;$\}//$ Shorthand System.out.print$()$

public static void PLN$($Object x$)\{$System$.$out.println$($x$)$;$\}//$ Shorthand System.out.println$()$

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