Question: Write a program using 8085 instruction set to perform the arithmetic operation 95 + 22 = 73 (95 = 2000H, 22 = 2020H) foe example:
Write a program using 8085 instruction set to perform the arithmetic operation 95 + 22 = 73 (95 = 2000H, 22 = 2020H)
foe example:

please no hand writing. thank you.
8085 Simulator File Tools Settings Simulation Load Sample Program Help 8085 Assembly Language Editor Registers; 0 O O Assembler Disassembler Register Value 76 Acumulator 00 0 08 BIT DECIMAL SUBSTRACTION Register B 00 OO juif 2nd no is greater than 1st no then the answer will in Zs complemer Register 00 O Register D 00 anually strore 1st 8 bitno in the memory location C050 OO anually store 2nd 8 bitno in the memory location C051 Register E 00 Result is stored in C052 Register H 00 Register 00 I Hemory(M) 00 LXIH C051 O WMA99 Resister Value SZ SUBM Flag Kesister 00 0 INRA DCXH ADD M Stack Pointer(SP) DAA Memory Pointer (HL) STACOS Program Status Word(PSW) HLT Program Counter(PC) Clock Cycle Counter WEXAMPLES 99-48 51 Instruction Counter STORE 0050-99 C051: URUN SOD SID INTR TRAP R75 2 - Tor SIM instruction SOD SDE R75 HS 0 1 For RIM instruction SID 17 5 16.5 15.5 0 O D IF Simulate Start F Run all At a Time Stop B No Corvetter Tool Hende Assemble 1
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