Write a short R function called missingMaxMin that accepts two paramters:

a$.$ A vector of numbers called InputNumbers, some of which may be missing $($i$.$e$.$ NA$)$

b$.$ An indicator variable MaxMin which has a value of either $1$ or $2$

i$.$ If MaxMin is $1,$ missing values in InputNumbers are replaced with the maximum value in InputNumbers

ii$.$ If MaxMin is $2,$ missing values in inputNumbers are replaced with the minimum value in InputNumbers

So for instance

x $<-$ c$(1\mathrm{.}2,7\mathrm{.}9,3\mathrm{.}4,$ NA$,4\mathrm{.}2,9\mathrm{.}1,$ NA$)$

z $<-$ missingMaxMin$($x$,1)$ #MaxMin is $1,$ so replace NA$$s with the maximum

z would now contain $(1\mathrm{.}2,7\mathrm{.}9,3\mathrm{.}4,9\mathrm{.}1,4\mathrm{.}2,9\mathrm{.}1,9\mathrm{.}1)$

hint $=$ remember to use the na$.$rm$=$T parameter when determining the max or min