Write a SQL query to return the company, website, and the similarity score $($jaccard$)$ between company and website with an alias 'similarity$\_$score'. For similarity score computation, you may want to convert both the company and website to the same case to return case$-$insensitive similarity score. Round the similarity score to two decimal places. Return only rows where the similarity score is greater than $0\mathrm{.}85$ or less than $0\mathrm{.}15.$ Sort the results by similarity score in descending order.