Write an equivalent expression using exponents:

a$.ln(x)=\frac{4}{5}$

b$.ln(\frac{N}{N_0})=-kt$

a$.e^x=ln(\frac{4}{5}),$ b$.e^{\frac{N}{N_0}}=ln(-kt)$

a$.x={10}^{\frac{4}{5}},$ b$.\frac{N}{N_0}={10}^{-kt}$

a$.x=e^{\frac{4}{5}},$ b$.\frac{N}{N_0}=e^{-kt}$

a$.x=\frac{4}{5}*e,$ b $*\frac{N}{N_0}=-kt*e$

a$.x=\frac{4}{5}*10,$ b$.\frac{N}{N_0}=-kt*10$