Question: Write the LEGv8 assembly code for the following loop. This code compares two character arrays and sets the variable different to 1 if they are


Write the LEGv8 assembly code for the following loop. This code compares two character arrays and sets the variable different to 1 if they are not the same // A and B are arrays of characters Cunsigned, 8-bits per element). int different = 0; int index = 0; while(11) != B[index]){ if(A[index] break; if(A[index] different = 1; '\0'){ == break; index++; Assume different is in X9, the base address of A is in X10 and the base address of B is in X11; index should go in X12 Label Instruction Description Initialize the value of 'different Initialize the value of 'index
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