Write the LEGv8 assembly code for the following loop. This code compares two character arrays and sets the variable different to 1 if they are not the same.

Question 2 26 pts Write the LEGV8 assembly code for the following loop. This code compares two character arrays and sets the variable different to 1 if they are not the same. // A and B are arrays of characters (unsigned, 8-bits per element). int different = 0; int index = 0; while(1 == 1) { if(A[index] != B[index]){ different = 1; break; if(A[index] == '\0'){ break; index++; Assume different is in X9, the base address of A is in X10 and the base address of Bis in X11; index should go in X12