Write the output that is printed when the given method below is passed each of the...

 

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Write the output that is printed when the given method below is passed each of the following maps and lists parameters. Recall that maps print in a (key1=value1, key2=value2, ..., keyN=valueN} format. Though hash maps usually have unpredictable ordering, for this problem, you should assume that when loop map or printing a map, it visits the keys in the order that they were added to the map or the order they are d below. If a map calls put () on a key that already exists, it replaces that key and keeps it in its current position ordering. public static void collectionMystery4 (HashMap<String, String> map, ArrayList<String: HashMap<String, String> result = new HashMap<String, String>(); for (int i Ø; i < list.size(); i++) { } } String = list.get (i); if (result.containsKey(s)) { } result.put(s, result.get(s) + result.get(s)); else if (map.containsKey(s)) { result.put (map.get(s), s); System.out .println(result); map (Marty-Stepp, Cynthia-Lee, Keith-Schwarz, Bruce-Lee, Mehran-Sahami); list = [Cynthia, Bruce, Lee, Eric, Schwarz, Keith, Sahami] map = (dog-woof, cat-meow, horse-whinny, frog-ribbit, duck-dog); list [dog, horse, dog, woof, meow, cat, meow, woof] Write the output that is printed when the given method below is passed each of the following maps and lists parameters. Recall that maps print in a (key1=value1, key2=value2, ..., keyN=valueN} format. Though hash maps usually have unpredictable ordering, for this problem, you should assume that when loop map or printing a map, it visits the keys in the order that they were added to the map or the order they are d below. If a map calls put () on a key that already exists, it replaces that key and keeps it in its current position ordering. public static void collectionMystery4 (HashMap<String, String> map, ArrayList<String: HashMap<String, String> result = new HashMap<String, String>(); for (int i Ø; i < list.size(); i++) { } } String = list.get (i); if (result.containsKey(s)) { } result.put(s, result.get(s) + result.get(s)); else if (map.containsKey(s)) { result.put (map.get(s), s); System.out .println(result); map (Marty-Stepp, Cynthia-Lee, Keith-Schwarz, Bruce-Lee, Mehran-Sahami); list = [Cynthia, Bruce, Lee, Eric, Schwarz, Keith, Sahami] map = (dog-woof, cat-meow, horse-whinny, frog-ribbit, duck-dog); list [dog, horse, dog, woof, meow, cat, meow, woof]

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Lets analyze the given method collectionMystery4 and then apply it to the provided maps and lists ja... View the full answer