Question: ( ( ' x ( ) - ( * ) ) N u W ( ( ' x - ( l su ) xX ooq

(('x()-(*)) NuW (('x-(l su)xX ooq x upl ll ll sooq l oN (('x-((l su))x(('x)()-() x sooq uW ooqxl upl(('x)((l(x))))\Lambda ((('x)())+(x))x\Lambda sooq l upl ll0 uonloS luonpou sooq ll sl o pl s0plq pl s'suo luonpodx'ooq oN 6 luonp slou soo8 uplq pl sooq luonp luonp sl soo9l upl llooq sooq ul ou sop ploS sooq lll upl lloN ooq lus sl ploS sooq l upl ll :ol pd u suus uollo ssdx luonp s x :(x) sl x : ('x)ooq s x : (x) pl s x : (x) :spd uollous\cap sun s uop soddnS 0lqosq u PZ07l ,plno uno pllnd d uI no u,plno u sq psul ooqx'd uI sq o no sunb llnd I plnos uM (uldxsld 'ou o soulnb ssuooqx pu ssu( :0 uosnb o pu sd oIOI

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