Question: ((x - 1)y + y' + y = ex Consider the initial-value problem y(1) = 1 y' (1)=-1 Does the Existence and Uniqueness Theorem

((x - 1)y" + y' + y = ex Consider the initial-value

((x - 1)y" + y' + y = ex Consider the initial-value problem y(1) = 1 y' (1)=-1 Does the Existence and Uniqueness Theorem guarantee the existence of a unique solution to this initial-v problem? Justify your answer. (DO NOT SOLVE THE DIFFERENTIAL EQUATION.)

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