Question: x e x d x = ( x - 1 ) e x + C , True / False d d x [ f -

xexdx=(x-1)ex+C, True/False
ddx[f-1(a)]=1f'(f-1(a)), True ?? False
If x>0, then ln(x8)=8ln(x)
True / False
4.ddx[x32]=ln(32)*x32-1
True / False
5.2xdx=1ln(2)2x+C
True / False
6. If f is continuous and 016f(x)dx=8, then 02x3f(x4)dx=2.
True / False
x e x d x = ( x - 1 ) e x + C , True / False d d

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