Question: X1153: No Dividing with 5 The method below takes in two integers as parameters and should throw an IllegalArgumentException if either parameter is the number

X1153: No Dividing with 5

The method below takes in two integers as parameters and should throw an IllegalArgumentException if either parameter is the number 5. In the conditional below, throw the required exception.

public int divideValues(int num, int denom) throws IllegalArgumentException { if (num == 5 || denom == 5) { } return num / denom; }

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