Question: xu + yu-v + 2u - 4 = 0 Given that the system of equations xu2 + y2v4 = 2 defines x and v implicitly

xu + yu-v + 2u - 4 = 0 Given that

xu + yu-v + 2u - 4 = 0 Given that the system of equations xu2 + y2v4 = 2 defines x and v implicitly as functions of y and u. Find du at the point P(x , y , u , v ) = (1, 1, 1, 1)

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