y -24 1.20 m 1) For q = 1nc, find the position P where the voltage...

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y -24 1.20 m 1) For q = 1nc, find the position P where the voltage is zero? (Hint: V=kQ/d, and the two charges will make a -(minus) and a +(plus) voltage, and adding the two voltages will make a zero value.) -K * 2 * q V1 >x is the unknown distance K * q V2 = →d2=(1.2-x) meter (1.2 – x) -K * 2 * q K * q VTotal = V1 + V½ = + (1.2 – x) Solve for x y -24 1.20 m 1) For q = 1nc, find the position P where the voltage is zero? (Hint: V=kQ/d, and the two charges will make a -(minus) and a +(plus) voltage, and adding the two voltages will make a zero value.) -K * 2 * q V1 >x is the unknown distance K * q V2 = →d2=(1.2-x) meter (1.2 – x) -K * 2 * q K * q VTotal = V1 + V½ = + (1.2 – x) Solve for x

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or x 24 120... View the full answer