Question: Y = 3 4 . 5 Do = 2 5 0 . 3 3 A composite column with a configuration shown in Figure Q 4

Y =34.5
Do =250.33
A composite column with a configuration shown in Figure Q4 is fixed at the base. The outer steel
tube diameter is D_(o)mm and the hollow ratio (ratio of inner tube diameter to outer tube diameter) is
0.7. Both steel tubes are having a similar thickness of 5 mm . An axial load of PkN is applied at the
top of the column through a rigid plate. Given the elastic modulus of concrete and steel, E_(c)=32GPa
and E_(s)=205GPa, concrete compressive strength, f_(cu)=Y MPa and steel yield strength, f_(y)=275MPa.
Solve the followings:
a) Generate the equilibrium and compatibility equations for this condition. (2%)
b) If the failure of the column is governed by concrete crushing, find the maximum axial load P .
(15%)
c) At the maximum load in (b), calculate the axial forces and normal stresses in the outer and inner
steel tubes. (8%)
Figure Q4
Y = 3 4 . 5 Do = 2 5 0 . 3 3 A composite column

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