$y=C_1{x}^{-2}+C_2{x}^{3}is$ the general solution $of{x}^2{y}^{\text{'}\text{'}}-6y=0.$ Find the solution that satisfies

the initial conditions $y(1)=6,y^{\text{'}}(1)=-2.$

$(a)y=2x^3+4x^{-2}$

$(b)y=4x^3-2x^{-2}$

$(c)y=4x^3+2x^{-2}$

$(d)y=3x^3+3x^{-2}$

$(e)$ None $of$ the above.