Question: Use the Nonlinear Shooting method with TOL = 104 to approximate the solution to the following boundary-value problems. The actual solution is given for comparison
Use the Nonlinear Shooting method with TOL = 10−4 to approximate the solution to the following boundary-value problems. The actual solution is given for comparison to your results.
a. y" = y3 -yy', 1≤ x ≤ 2, y(1) = 1/2, y(2) = 1/3; use h = 0.1; actual solution y(x) = (x +1) −1.
b. y" = 2y3 − 6y − 2x3, 1 ≤ x ≤ 2, y(1) = 2, y(2) = 5/2; use h = 0.1; actual solution y(x) = x + x−1.
c. y" = y' + 2(y−ln x)3 −x−1, 2 ≤ x ≤ 3, y(2) = 1/2 + ln 2, y(3) = 1/3 + ln 3; use h = 0.1; actual solution y(x) = x−1 + ln x.
d. y" = 2(y')2x−3 − 9y2x−5 + 4x, 1≤ x ≤ 2, y(1) = 0, y(2) = ln 256; use h = 0.05; actual solution y(x) = x3 ln x.
Step by Step Solution
3.34 Rating (178 Votes )
There are 3 Steps involved in it
The Nonlinear Shooting Algorithm gives the results in the following tables ... View full answer
Get step-by-step solutions from verified subject matter experts
Document Format (1 attachment)
731-M-N-A-N-L-A (980).docx
120 KBs Word File
