You push a $15\mathrm{.}0$ kg lawnmower across the lawn at constant speed. To do so$,$ you exert $120$N of force along the handle, which makes an angle of $35$ degree with the horizontal; 

$($a$)$ Draw the force diagram of the lawnmower; 

$($b$)$ Create the table of force components for the lawnmower; 

$($c$)$ Calculate the normal force on the lawnmower; 

$($d$)$ Calculate the friction force on the lawnmower; $$

$($e$)$ you now push with a force of $125$ N on the lawnmower at the same angle and notice that you acceleration $-$ calculate the normal force on the lawnmower, calcuate the friction on the lawnmower if the coefficient of friction is $0\mathrm{.}455,$ calculate the acceleration of the lawnmower.  

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a The force diagram of the lawnmower can be represented as follows Tilted 35 degrees The force of 12... View the full answer