1. You are given a fair dice (if you roll it, the side facing up will be 1, 2, 3, 4, 5, or 6 with equal probability). Now you play the following game with your teammate.
2. You and your teammate roll the dice in turn. Each turn, a player can choose to repeatedly roll a dice or choose to hold at any time. During your turn, if 1 is rolled, you score nothing for this turn and it is your teammate's turn; if 6 is rolled, you score -2 points for this turn and it is your teammate's turn.
3. More specifically, at any time during your turn, you need to make two decisions:
4. 1) Roll
5. - if you roll a 1, you score nothing for this turn and it becomes your

teammate's turn;

• -if you roll a 6, your score -2 points for this turn and it becomes your
• teammate's turn;
• -if you roll a 2-5, the number is added to your total score;

2) Hold

- you choose not to roll for this turn anymore and the turn total is

added to your total score.

For example, assume that your current total score is 8 and during your turn,

• -if you roll 2, 3, 4, 1, then your score for this turn is 0 and your total score is 8 (8+0). Now it is your teammate's turn.
• -if you roll 2, 3, 4, and choose to hold, your score for this turn is 9 (2+3+4) and your total score will be 17 (8+9). Now it is your teammate's turn.
• -if you roll 2, 4, 6, your score for this turn is -2 and your total score is 6 (8-2). Now it is your teammate's turn.

Question: A player decides to roll 3 times during the turn unless he/she rolls a 1 or 6, what is the probability that he/she will score more than 0 points for this turn?