Question: You are given a hash function f1(x-x % 5, where x is the value to be hashed and f(x) is the hash address. Double hashing

You are given a hash function f1(x-x % 5, where x is the value to be hashed and f(x) is the hash address. Double hashing is used to resolve collisions and f2(x)-1 + x%3. An ith probe collision is resolved by ( f1(x) + f2(x) )% 5 The hash function receives the input 6, 4, 11, 10 13) in that order. Place each number in the hash table at its correct address. Address 1 2 3 4
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