You are given a red coin and a blue coin. Both coins have the number 1...

 

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You are given a red coin and a blue coin. Both coins have the number 1 on one side and the number 2 on the other side. You flip both coins once (independently of each other) and take the sum of the two results. Define the events A B C = "the sum of the results equal 2", "the sum of the results equals 3", "the sum of the results equals 4". Assume both coins are fair. Determine Pr(A), Pr(B), and Pr(C). Show your work. • Let p and q be real numbers with 0 < p < 1 and 0 <q < 1. Assume the red coin comes up "1" with probability p and the blue coin comes up "1" with probability q. Is it possible to choose p and q such that Pr(A) = Pr(B) = Pr(C')? As always, justify your answer. You are given a red coin and a blue coin. Both coins have the number 1 on one side and the number 2 on the other side. You flip both coins once (independently of each other) and take the sum of the two results. Define the events A B C = "the sum of the results equal 2", "the sum of the results equals 3", "the sum of the results equals 4". Assume both coins are fair. Determine Pr(A), Pr(B), and Pr(C). Show your work. • Let p and q be real numbers with 0 < p < 1 and 0 <q < 1. Assume the red coin comes up "1" with probability p and the blue coin comes up "1" with probability q. Is it possible to choose p and q such that Pr(A) = Pr(B) = Pr(C')? As always, justify your answer.

Answer rating: 100% (QA)

Part 1 Probabilities under equal heads probabilities Event A Sum of results equals 2 one 1 and one 2 ... View the full answer