You are supposed to find the minimum required transmit power, Prx (dBW), in a mobile communication system through link budget analysis. The path-loss is worse than that in free-space propagation due to the attenuation caused by objects: Path-loss (in linear scale): PL = (4nf/c)2d35, where c=3x108 m/sec. From the temperature (7-290K) and the noise figure (F-6 dB), the noise power can be calculated: Noise power (in dBW): P = -228.6 + 10 log107K] + 10 log10B[Hz] + F. The total antenna gain of transmitter and receiver is 25 dB. For satisfactory performance, the minimum required signal-to-noise ratio at the receiver is 10 dB. The carrier frequency is f=2 GHz, and the transmission bandwidth is 5 MHz. (a) Sketch a graph of the required transmitter power in dBW as a function of distance between the transmitter and receiver from 0.1 km. to 10 km. (Plot distance on a logarithmic scale; that is, put the ticks of your horizontal axis at 0.1 km, 1 km, and 10 km.) (b) Discuss the advantages and disadvantages of using a carrier frequency of 700 MHz, instead of 2 GHz, for the radio transmission of this type of signal in the context of providing coverage.