You are testing the null hypothesis that the proportion of students using Unix computers is 0.40 against the two tailed alternative. A random sample of 300 students calculated the sample proportion to be 0.45. Using a 5% level of significance 0 one would reject the null since the pvalue is approximately 0.35 and the probability of rejecting the null is almost 91%. 0 one would not reject the null since the pvalue is approximately 0.0385 and the power of the test if the true proportion is 0.37 is about 81%. 0 one would not reject the null since the pvalue is approximately 0.29 and the probability of not rejecting the null when the true proportion is 0.37 is almost 81%. 0 one would reject the null since the pvalue is approximately 0.01 and the probability of not rejecting the null when the true proportion is 0.37 is almost 81%. 0 one would not reject the null since the pvalue is approximately 0.0385 and the probability of rejecting the null when the true proportion is 0.37 is almost 0.19