You are testing the null hypothesis that the proportion of students using Windows computers is 0.15 against the two tailed alternative. A random sample of 200 students calculated the sample proportion to be 0.15. Using a 9% level of significance 0 one would not reject the null since the pvalue is over 0.045 and if the true proportion is 0.15 the beta of the test is not defined. 0 one would reject the null since the pvalue is approximately 0.01 and the probability of not rejecting the null when it is false is almost 33%. 0 one would not reject the null since the pvalue is approximately 0.81 and when the true proportion is 0.15, the probability of not rejecting the null when it is false is almost 13%. 0 one would reject the null since the pvalue is approximately 0.35 and the probability of rejecting the null is almost 91%. 0 one would not reject the null since the pvalue is approximately 0.29 and when the true proportion is 0.15, the probability of not rejecting the null when it is true is almost 13%