you cannot review this problem again. You can use printf() to debug your code. The printf()...

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you cannot review this problem again. You can use printf() to debug your code. The printf() may not work in case of syntax/runtime error. The version of GCC being used is 5.5.0. The Torns County Visa Center generates the token number for its applicants from their application ID. The application ID is a numeric value. The token number is generated in a specific form. The even digits in the applicant's ID are replaced by the digit one greater than the even digit and the odd digits in the applicant's ID are replaced by the digit one lesser than the odd digit. The numeric value thus generated represents the token number of the applicant. Write an algorithm to generate the token number from the applicant ID. Input The input consists of an integer-applicant/D, representing the application ID of the applicant Output Print an integer representing the token number. Constraint 0<applicantlD≤ 10⁹ Note 0 is considered as an even digit and 1 is Test Cases & Output Editor 1 // Sample code to read input and write output: 2 3- / 4 #include <stdio.h> 5 6 int main() 7 + { 8 9 10 11 12 } 13 */ 14 15 // Warning: Printing unwanted or ill-formatted data to output idll cause the test cases to fail 16 17 #include<stdio.h> 18 19 int main() 20 - { 21 22 23 24 25- 26 27 28 29 30 - 31 32 33 char name[20]; scanf("%s", name); printf("Hello %s", name); return 0; 34 35 ) // Write your code here int n; if(n%2==0) { } else ( n=n+1; n=(n%10); I nun-1; } printf(n); return 0; // Read input from STOIN // Write output to STDOUT Input The input consists of an integer - applicantlD, representing the application ID of the applicant. Output Print an integer representing the token number. Constraint 0<applicantlD < 10⁹ Note O is considered as an even digit and 1 is considered as an odd digit. Example Input 245567 Output 354476 Explanation The first digit in the application ID is '2' i.e even. It is replaced by one greater digit i.e 3. The second digit is '4' i.e even. It is replaced by one greater digiti.e 5. The third digit is '5' i.e odd. It is replaced by one lesser digit i.e 4 and so on. Hence the output is 354476. 3- /* 4 #include <stdio.h> 5 6 int main() 7 - { 8 9 10 11 12 13 18 19 20 21 22 23 24 25- 26 27 28 29 ) 14 15 // Warning: Printing unwanted or ill-formatted data to output will cause the test cases to fall 16 17 #include<stdio.h> 30 - 31 32 33 / char name[20]; scanf("%s", name); printf("Hello %s", name); return 0; int main() { 34 35 } // Write your code here int n; if(n%2==0) { n=n+1; n=(n%10); } else { n=n-1; // Read input from STDIN // Write output to STDOUT } printf(n); return 0; you cannot review this problem again. You can use printf() to debug your code. The printf() may not work in case of syntax/runtime error. The version of GCC being used is 5.5.0. The Torns County Visa Center generates the token number for its applicants from their application ID. The application ID is a numeric value. The token number is generated in a specific form. The even digits in the applicant's ID are replaced by the digit one greater than the even digit and the odd digits in the applicant's ID are replaced by the digit one lesser than the odd digit. The numeric value thus generated represents the token number of the applicant. Write an algorithm to generate the token number from the applicant ID. Input The input consists of an integer-applicant/D, representing the application ID of the applicant Output Print an integer representing the token number. Constraint 0<applicantlD≤ 10⁹ Note 0 is considered as an even digit and 1 is Test Cases & Output Editor 1 // Sample code to read input and write output: 2 3- / 4 #include <stdio.h> 5 6 int main() 7 + { 8 9 10 11 12 } 13 */ 14 15 // Warning: Printing unwanted or ill-formatted data to output idll cause the test cases to fail 16 17 #include<stdio.h> 18 19 int main() 20 - { 21 22 23 24 25- 26 27 28 29 30 - 31 32 33 char name[20]; scanf("%s", name); printf("Hello %s", name); return 0; 34 35 ) // Write your code here int n; if(n%2==0) { } else ( n=n+1; n=(n%10); I nun-1; } printf(n); return 0; // Read input from STOIN // Write output to STDOUT Input The input consists of an integer - applicantlD, representing the application ID of the applicant. Output Print an integer representing the token number. Constraint 0<applicantlD < 10⁹ Note O is considered as an even digit and 1 is considered as an odd digit. Example Input 245567 Output 354476 Explanation The first digit in the application ID is '2' i.e even. It is replaced by one greater digit i.e 3. The second digit is '4' i.e even. It is replaced by one greater digiti.e 5. The third digit is '5' i.e odd. It is replaced by one lesser digit i.e 4 and so on. Hence the output is 354476. 3- /* 4 #include <stdio.h> 5 6 int main() 7 - { 8 9 10 11 12 13 18 19 20 21 22 23 24 25- 26 27 28 29 ) 14 15 // Warning: Printing unwanted or ill-formatted data to output will cause the test cases to fall 16 17 #include<stdio.h> 30 - 31 32 33 / char name[20]; scanf("%s", name); printf("Hello %s", name); return 0; int main() { 34 35 } // Write your code here int n; if(n%2==0) { n=n+1; n=(n%10); } else { n=n-1; // Read input from STDIN // Write output to STDOUT } printf(n); return 0;

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