You may have a combination lock on your locker at school where you have to spin the dial to $3$ separate numbers from $0$ up to $40.$ What if you forgot your combination? Would you be able to guess it$?$

Write code that will generate $3$ random integers from $0$ up to $40($but not including $40)$ using Math.random$()$ in the Active Code window below. Run it a couple times to see it generate different numbers.

How many times would you need to run it to guess your combination correctly? Let's have the code compute the number of permutations possible in your combination lock using Math.pow$($number$,$exponent$).$ For example, if you had $2$ dials on your combination lock where each dial can be set to a digit from $0-9(10$ digits$),$ there are $102$ possible permutations. In Java, this would be written as Math.pow$(10,2)$ which means $10$ to the power of $2.$ If you start listing all the permutations possible, you can tell that there are $102$ or $100$ possible permutations for a $2$ dial lock from $0-9.$

$00,01,02,03,04,05,06,07,08,09$

$10,11,12,13,14,15,16,17,18,19$

dots

$90,91,92,93,94,95,96,97,98,99$

Now what about the combination lock for this challenge? It has $3$ dials with $0-40($not including $40)$ numbers possible on each dial. In general, the formula to use is NumbersPerDialnumberOfDials. Write this using the Math.pow$()$ method in your code and save it into a variable and print out.