Your calculation for the total work done on the sled is mostly correct, but let's go through the steps again to ensure accuracy: Step 1: Calculate the work done by the applied force The work done by a force is calculated using: \[ W_{\text{applied}} = F \cdot s \cdot \cos(\theta) \] Given: - \( F = 200 \, \text{N} \) - \( s = 15 \, \text{m} \) - \( \theta = 23.2^\circ \) Calculate \( \cos(23.2^\circ) \): \[ \cos(23.2^\circ) \approx 0.9205 \] Substitute the values into the formula: \[ W_{\text{applied}} = 200 \times 15 \times 0.9205 \approx 2761.5 \, \text{J} \] Step 2: Calculate the work done by the frictional force The frictional force opposes the direction of motion, so: \[ W_{\text{friction}} = -f_{\text{friction}} \cdot s \] Given: - \( f_{\text{friction}} = 40 \, \text{N} \) - \( s = 15 \, \text{m} \) \[ W_{\text{friction}} = -40 \times 15 = -600 \, \text{J} \] Step 3: Calculate the total work done The total work done \( W \) is the sum of the work done by the applied force and the work done by friction: \[ W = W_{\text{applied}} + W_{\text{friction}} \] Substitute the calculated values: \[ W = 2761.5 \, \text{J} + (-600 \, \text{J}) = 2161.5 \, \text{J} \] There seems to have been a slight calculation error previously. The correct total work done on the sled is \( 2161.5 \, \text{J} \). GRASS Method Must Be Used For Full Marks