Question: Show that if (mathbf{X}^{prime} mathbf{X}) is in correlation form, (boldsymbol{Lambda}) is the diagonal matrix of eigenvalues of (mathbf{X}^{prime} mathbf{X}), and (mathbf{T}) is the corresponding matrix
Show that if \(\mathbf{X}^{\prime} \mathbf{X}\) is in correlation form, \(\boldsymbol{\Lambda}\) is the diagonal matrix of eigenvalues of \(\mathbf{X}^{\prime} \mathbf{X}\), and \(\mathbf{T}\) is the corresponding matrix of eigenvectors, then the variance inflation factors are the main diagonal elements of \(\mathbf{T} \mathbf{\Lambda}^{-1} \mathbf{T}^{\prime}\).
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