Energy gained (or lost) by an electric charge q traveling in an electric field is qv, where
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Energy gained (or lost) by an electric charge q traveling in an electric field is qv, where v is the electric potential gained (or lost). In a capacitor with charge Q and terminal voltage V, let all charges go from one plate to the other. By way of computation, show that the total energy W gained (or lost) is not QV but QV/2 and explain why. Also note that QV/2 is equal to the initial energy content of the capacitor.
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Related Book For 
Schaum S Outline Of Electric Circuits
ISBN: 9781260011968
7th Edition
Authors: Mahmood Nahvi, Joseph Edminister
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