The sole of a man’s size-10 shoe is around 11.0 in. by 4.00 in. Determine the gauge pressure under the feet of a 200-lb man standing upright. Give your answer in both lb/in.² and Pa. [1.00 lb/in2 = 6895 Pa. Check your work using 1.00 in.² = 6.45 × 10^–4 m² and 1.00 lb = 4.448 N.]