Consider now the Doppler effect in wireless communications. The difference in velocity between the transmitter and the
Question:
where α is the attenuation and Ï is the Doppler frequency shift which is typically much smaller than the signal frequency. Let Ω0 = Ï, Ï = Ï/100, and α = 0.7. This is analogous to the case where the received signal is the sum of the line of sight signal and an attenuated signal affected by Doppler.
(a) Consider the term αejÏt a phasor with frequency Ï = Ï/100 to which we add 1. Use the MATLAB plotting function compassto plot the addition 1 + 0.7 ejÏt for times from 0 to 256 sec changing in increments of T = 0.5 sec.
(b) If we write y(t) = A(t)ej(Ω0t + θ(t)) give analytical expressions for A(t) and θ(t), and compute and plot them using MATLAB for the times indicated above.
(c) Compute the real part of the signal
y1(t) = x(t) + 0.7x(t 100)ejÏ(t100)
i.e., the effects of time and frequency delays, put together with attenuation, for the times indicated in part (a). Use the function sound(let Fs =2000 in this function) to listen to the different signals.
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