Let Y have a truncated distribution with pdf g(y) = (y)/[(b)(a)], for a < y < b,

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Let Y have a truncated distribution with pdf g(y) = φ(y)/[Φ(b)−Φ(a)], for a < y < b, zero elsewhere, where φ(x) and Φ(x) are, respectively, the pdf and distribution function of a standard normal distribution. Show then that E(Y) is equal to [φ(a) − φ(b)]/[Φ(b) − Φ(a)].

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Related Book For  answer-question

Introduction To Mathematical Statistics

ISBN: 9780321794710

7th Edition

Authors: Robert V., Joseph W. McKean, Allen T. Craig

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