Question: 9.27 P-value for small samples Example 4, on whether dogs can detect bladder cancer by selecting the correct urine specimen (out of seven), used the
9.27 P-value for small samples Example 4, on whether dogs can detect bladder cancer by selecting the correct urine specimen (out of seven), used the normal sampling distribution to find the P-value. The normal distribution P-value approximates a P-value using the binomial distribution.
That binomial P-value is more appropriate when either expected count is less than 15. In Example 4, n was 54, and 22 of the 54 selections were correct.
a. If H0: p = 1>7 is true, X = number of correct selections has the binomial distribution with n = 54 and p = 1>7. Why?
b. For Ha: p 7 1>7, with x = 22, the small sample P-value using the binomial is P1222 +P1232 +g+P1542, where P(x) denotes the binomial probability of outcome x with p = 1>7. (This equals 0.0000019.) Why would the P-value be this sum rather than just P(22)?
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