More generally, using the notation of the previous exercise, show that, for i > j > , hi (x)hj (x)hk (x) (x)dx = i!j!k!

More generally, using the notation of the previous exercise, show that, for i

> j > κ,

∫ hi (x)hj (x)hk (x)ϕ (x)dx = i!j!k!
{
1 2 (j+k−i)}!{
1 2 (i+k−j)}!{
1 2 (i+j−k)}!
when j+k−i is even and non-negative, and zero otherwise, (Jarrett, 1973, p. 26).