Use the data from Example 8.11 involving citizens opinions about a bond proposal, reproduced here.

Suppose that the citizens in the developing section of the city have no opinion about this proposal, so that they are equally likely to favor as oppose the proposal. Test : =.5 0 H p against : .5 a H p≠ .
1. Select Stat ➤ Basic Statistics ➤ 1 Proportion, select Summarized data in the top drop-down list and enter the values for x and n in the appropriate boxes. Click the radio button marked “Perform hypothesis test” and enter the value .5.
2. In the Options dialog box, make sure that the alternative hypothesis is two-tailed and choose “Normal approximation” in the Method drop-down list (Figure 9.16(a)). Click OK twice to obtain the output—z =3.68 with p-value50.000—shown in Figure 9.16(b).
The results are highly significant. There is evidence that the citizens in the developing section DO have an opinion about this proposal!

Developing Section Rest of the City Sample Size 50 100 Number Favoring Proposal 38 65