Consider the circuit in Figure P10.34. The transistors are matched. Assume that base currents are negligible and that \(V_{A}=\infty\). Using the current-voltage relationships given by Equations (10.26(a)) and (10.26(b)), show that

\[I_{O} R_{E 2}-I_{\mathrm{REF}} R_{E 1}=V_{T} \ln \left(\frac{I_{\mathrm{REF}}}{I_{O}}\right)\]

If \(R_{E 1}=R_{E 2} eq 0\) and \(V_{A} eq \infty\), explain the advantage of this circuit over the basic two-transistor current source in Figure 10.2(b).

Equation 10.26 a and b:-

Figure 10.2(b):-

Transcribed Image Text:

V+ IREF R ww www 22 REL RE2 Figure P10.34 V-