Question: A (69-mathrm{kV}) circuit breaker has a voltage range factor (mathrm{K}=1.25), a continuous current rating of (1200 mathrm{~A}), and a rated short-circuit current of 19,000 A
A \(69-\mathrm{kV}\) circuit breaker has a voltage range factor \(\mathrm{K}=1.25\), a continuous current rating of \(1200 \mathrm{~A}\), and a rated short-circuit current of 19,000 A at the maximum rated voltage of \(72.5 \mathrm{kV}\). Determine the maximum symmetrical interrupting capability of the breaker. Also, explain its significance at lower operating voltages.
Step by Step Solution
3.34 Rating (163 Votes )
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
