Question: For a single-phase, two-wire line consisting of two solid cylindrical conductors of same radius, (r), the total circuit inductance, also called loop inductance, is given
For a single-phase, two-wire line consisting of two solid cylindrical conductors of same radius, \(r\), the total circuit inductance, also called loop inductance, is given by (in \(\mathrm{H} / \mathrm{m}\) )
(a) \(2 \times 10^{-7} \ln \left(\frac{\mathrm{D}}{r^{\prime}}ight)\)
(b) \(4 \times 10^{-7} \ln \left(\frac{\mathrm{D}}{r^{\prime}}ight)\)
where \(r^{\prime}=e^{-\frac{1}{4}} r=0.778 r\)
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The correct answer is b 4 times 107 ln leftfracmathrmDrprime ight The formula for the total circuit ... View full answer
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