Question: Why might a programmer choose to represent a data item in IEEE binary128 floating-point format instead of IEEE binary64 floating-point format? What additional costs might

Why might a programmer choose to represent a data item in IEEE binary128 floating-point format instead of IEEE binary64 floating-point format? What additional costs might be incurred at runtime (when the application program executes) as a result of using the 128-bit instead of the 64-bit format?

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