Question: Derive eq. (30.15) by equating the normal force per unit length on a blade element given in eq. (30.12) with the thrust per unit length

Derive eq. (30.15)

8πα K sin o Àc B


by equating the normal force per unit length on a blade element given in eq. (30.12)

pOK Bu2(1 – a)²c ST =-K Bu q sino 2 2, 2 sin o oK Bu²(1 – a)²cj cos o SN=;P0K Bw²cj cos o f =- ø î: 2 sin?


with the thrust per unit length obtained from the axial momentum analysis (30.14)

8 K sin o c B pOK Bu2(1 a)c ST =-K Bu.

8 K sin o c B pOK Bu2(1 a)c ST =-K Bu q sino 2 2, 2 sin o oK Bu(1 a)cj cos o SN=;P0K Bwcj cos o f =- : 2 sin?

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