Show that a charged particle moving in the plane perpendicular to a constant magnetic field (eq. (19.29)
Question:
Show that a charged particle moving in the plane perpendicular to a constant magnetic field (eq. (19.29)
moves in a circle with Br = mv/q. What is the radius of the circle for an electron with energy 15 keV in a 10 Tesla magnetic field (typical of ITER)? What is the radius for a proton?
F = qE + qv x B +qv ×
Step by Step Answer:
The magnetic force on a charged particle is given by eq 345 Since the force ...View the full answer
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