Question: =+8. Show that eA+B = eAeB = eBeA when AB = BA. (Hint: Prove that all three functions et(A+B) , etAetB, and etBetA satisfy the
=+8. Show that eA+B = eAeB = eBeA when AB = BA. (Hint: Prove that all three functions et(A+B)
, etAetB, and etBetA satisfy the ordinary differential equation P
(t)=(A + B)P(t) with initial condition P(0) = I.)
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